3 var result = document.getElementById("link");
7 ajax.onreadystatechange = getData;
9 result.innerHTML = "onreadystatechange error!"
13 ajax.open("GET","//localhost:8000/images/"+document.cameracontrol.input.value+".tif",true);
14 ajax.responseType = 'blob'
16 result.innerHTML = "ajax open error!";
22 result.innerHTML = "send error!";
25 result.innerHTML = "you cannot use ajax...";
29 if(ajax.readyState == 4){
30 if(ajax.status == 200){
31 var url = window.URL.createObjectURL(this.response)
32 dl_name = document.cameracontrol.dlname.value+"_"+document.cameracontrol.mode.value;
33 result.innerHTML = '<a href="'+url+'" download='+dl_name+'>download_link</a>';
35 result.innerHTML = "HTTP error!";
38 result.innerHTML = "HTTP Transmission!";