1 ! Like vector_subscript_1.f90, but check subscripts in multi-dimensional
6 integer, parameter :: n = 5
8 integer, dimension (n, n, n) :: a, b
9 integer, dimension (n) :: idx, id
11 idx = (/ 3, 1, 5, 2, 4 /)
12 id = (/ (i1, i1 = 1, n) /)
13 forall (i1 = 1:n, i2 = 1:n, i3 = 1:n)
14 b (i1, i2, i3) = i1 + i2 * 10 + i3 * 100
18 a (foo (i1), 1, :) = b (2, :, foo (i1))
21 if (a (idx (i1), 1, i2) .ne. b (2, i1, idx (i2))) call abort
26 a (1, idx (1:4), 2:4) = b (2:5, idx (3:5), 2)
29 if (a (1, idx (i1), 1 + i2) .ne. b (1 + i1, idx (i2 + 2), 2)) call abort
36 integer, dimension (n) :: foo