memset (data, 0, sizeof (*data));
- /* NAMED_ARG is a mis-nomer. We really mean 'non-varadic'. */
+ /* NAMED_ARG is a misnomer. We really mean 'non-variadic'. */
if (!cfun->stdarg)
- data->named_arg = 1; /* No varadic parms. */
+ data->named_arg = 1; /* No variadic parms. */
else if (TREE_CHAIN (parm))
- data->named_arg = 1; /* Not the last non-varadic parm. */
+ data->named_arg = 1; /* Not the last non-variadic parm. */
else if (targetm.calls.strict_argument_naming (&all->args_so_far))
- data->named_arg = 1; /* Only varadic ones are unnamed. */
+ data->named_arg = 1; /* Only variadic ones are unnamed. */
else
- data->named_arg = 0; /* Treat as varadic. */
+ data->named_arg = 0; /* Treat as variadic. */
nominal_type = TREE_TYPE (parm);
passed_type = DECL_ARG_TYPE (parm);
emit_insn_before (insns, insn);
/* Now replace all mentions of the input with output. We can't
- just replace the occurence in inputs[i], as the register might
+ just replace the occurrence in inputs[i], as the register might
also be used in some other input (or even in an address of an
output), which would mean possibly increasing the number of
inputs by one (namely 'output' in addition), which might pose
Here 'input' is used in two occurrences as input (once for the
input operand, once for the address in the second output operand).
- If we would replace only the occurence of the input operand (to
+ If we would replace only the occurrence of the input operand (to
make the matching) we would be left with this:
output = input